Continuity
A real valued function is continuous at a point in its domain if the limit of the function at that point equal the value of the function at that point. A function f is continous at an interior point x = c of its domain if limx→cf(x) = f(c).
Differentiability
Suppose f(x) is a real valued function and x=c is a point in its domain. The derivative of f(x) at x=c is defined by limx→c( f(x)-f(c))/x-c or limh→0( f(c+h)-f(c))/h provided this limit exists. Then the function defined by limh→0( f(x+h)-f(x))/h wherever the limit exists, is defined to be derivative of f(x). The process of finding the derivative of a function is called differentiation w.r.t x.
Chain Rule
Let f be a real valued function which is a composite of two functions u and v; i.e. f = vou. Suppose t = u(x) and if both dt/dx and dv/dx exists, we ave,df/dx=dv/dt.dt/dx
Derivative Of Inverse Trigonometric Function
f(x) | sin-1 x | cos-1 x | tan-1 x | cot-1 x | sec-1 x | cosec-1 x |
f'(x) | $$\frac{1}{\sqrt[\normalsize]{1-x^2}}$$ | $$\frac{-1}{\sqrt[\normalsize]{1-x^2}}$$ | $$\frac{1}{1+x^2}$$ | $$\frac{-1}{1+x^2}$$ | $$\frac{1}{\sqrt[\normalsize{x}]{1-x^2}}$$ | $$\frac{-1}{\sqrt[\normalsize{x}]{1-x^2}}$$ |
---|
Derivative Of Implicit Functions
If the variables x and y are connected by the relation of the form f(x,y) = 0 and it is not possible to express y as a function of x in the form y = φ(x), then y is called an implicit function of x. In such case, we differentiate dφ/dy.dy/dx
Logarithmic Differentiation
Derivative Of Functions Expressed In Parametric Forms
If x = φ(t) and y = φ(t) are two functions and t is a variable. In such cases x and y are called parametric functions and t is called the parameter. By chain rule we get; dy/dx=φ'(t)/φ'(t)
Second Order Derivatives
Mathematics Most Likely Question Bank
CBSE Class 12 for 2025 Exam