Complex Numbers And Quadratic Equations Class 11 Notes Mathematics Chapter 5 - CBSE
Chapter : 5
What Are Complex Numbers And Quadratic Equations ?
Complex Number
A number of the form (a + ib) where a and b are real numbers is defined to be a complex numbers.
$$\text{e.g. : 2+3i, -1+}\sqrt{3}\space i$$
Algrebra Of Complex Numbers
Addition of two complex numbers
Let z1 = a + ib and z2 = c + id be any two complex numbers.
Then z1 + z2 = (a + ib) + (c + id) = (a + c) + i(b + d)
Difference of two complex numbers
Given, any two complex number z1 and z2 , then difference,
z1 – z2 = z1 + (– z2) ⇒ (a + ib) – (c + id)
= (a + ib) + (– c – id)
= (a – c) + i(b – d)
Multiplication of two complex numbers
Let z1 = a + ib and z2 = c + id be two complex numbers.
Then product z1 z2 = (a + ib)(c + id) = ac – bd + i(ad + bc)
Division or two complex number
Let any two complex numbers z1 and z2 ,
where z2 ≠ 0, then quotient
$$\frac{z_{1}}{z_{2}}= \frac{z_{1}.1}{z_{2}}$$
Power of i
We know that
i3 = i2 × i = (– 1)i = – i
i4 = i2 × i2 = – 1 × – 1 = 1
i5 = (i2) 2 × i = (– 1)2 i = i, etc.
$$\text{Also\space}i^{\normalsize-1}=\frac{1}{i}× \frac{i}{i}=\frac{i}{i^{2}} = -i\\i^{\normalsize-2}=\frac{1}{i^{2}}=-1$$
In general, for any integer
i4k = 1, i4k + 1 = i, i4k + 2 = – 1, i4k + 3 = i
The square roots of negative real numbers
Note that i2 = –1 and (– i)2 = i2 = –1.
Therefore, the square roots of –1 are i, – i.
However, by the symbol $$\sqrt{\normalsize-1}$$ , we should mean i only.
Identities
$$\centerdot\space\text{(z}_1 + \text{z}_2)^2 =\\ z_1^2 + z_2^2 + 2z_1z_2\\\centerdot\space(Z_{1} - Z_{2})^{2} =\\ Z_{1}^{2} - 2Z_{1}Z_{2} + Z_{2}^{2}\\\centerdot\space (z_{1} + z_{2})^{3} =\\ z_{1}^{3}+ 3z_{1}^{2}z_{2}+3Z_{1}Z_{2}^{2}+z_{2}^{3}\\\centerdot\space(Z_{1}-Z_{2})^{3} =\\ z_{3}^{3}- 3z_{1}^{2}z_{2} + 3z_{1}z_{2}^{2}- z_{2}^{2}\\\centerdot\space z_{1}^{2} - z_{2}^{2}=\\\text{(z}_{1} + z_{2})(z_{1}-z_{2})$$
The Modulus And Conjugate Of The Complex Numbers
Let z = a + ib be a complex number. Then the modulus of z, denoted by |z|. If z = a + ib then conjugate is represented by
$$\bar{z} =\text{a + ib}\\\therefore\space|z| =\sqrt{a^{2} + b^{2}}\\\text{and}\space\bar{z} = a - ib\\\centerdot|z_{1} z_{2}| =|Z_{1}||Z_{2}|\\\centerdot\space\bigg|\frac{z_{1}}{z_{2}}\bigg|=\bigg|\frac{z_{1}}{z_{2}}\bigg|\\\text{provided}\space |z_{2}|\neq 0\\\centerdot\space Z_{1}Z_{2} =\bar{z}_{1}\bar{z}_{2}\\\centerdot\space \overline{z_{1}\pm z_{2}} = \bar{z}_{1} + \bar{z}_{2}\\\centerdot\space \bigg(\frac{\bar{z}_{1}}{\bar{z}_{2}}\bigg)=\frac{\bar{Z}_{1}}{\bar{Z}_{2}}\\\text{provided |z}_2| ≠ 0$$
Argand Plane And Polar Representation
The polar form of the complex number z = x + iy is r(cos θ + i sin θ)
$$\text{where r =}\sqrt{x^{2} + y^{2}}\\\text{(the modulus of z) and}\\\text{cos}\space\theta = \frac{x}{r},\space \text{sin}\space\theta=\frac{y}{r}\\\text{(}\theta\space \text{is known as the argument of z.)}$$
The value of θ, such that – π ≤ θ ≤π is the principal argument of z.
Quadratic Equations
The solutions of the quadratic equation ax2+ bx + c = 0 where a, b, c ∈ R a ≠ 0,
$$\text{b}^{2} - 4ac \lt 0\space\text{are given by}\\ x =\frac{-b\pm\sqrt{b^{2} - 4ac}}{2a}$$
A polynomial equation of degree n has n roots.
