Physics Unsolved Sample Paper Solutions ISC Class 12

Section-A

Answer 1.

  • (A) (i) (a) zero
  • (ii) (b) Alexander’s dark band is formed between primary and secondary rainbow because light is absorbed in this region.
  • (iii) (c) 0.3853 × 1007C
  • (iv) (b) 2
  • (v) (b) εr F
  • (vi) (d) 16r
  • (vii) (d) gamma rays

(B) (i) Magnetic induction due to an infinitely long straight wire =µ0I/2πa ...(i)

Magnetic induction due to the circular coil carrying current at its centre=µ0nI/2a ...(ii)

Dividing equations (i) and (ii)

238

(ii) Magnetic induction due to circular coil carrying current at its centre = µ0nI/2a ...(i)

Magnetic induction due to the arc = µ0Il/4πR2 ...(ii)

According to question,

Magnetic induction due to circular coil = Magnetic induction due to the arc

239

(iii) In a n-type semiconductor, electrons are majority charge carriers and holes are minority charge carriers.

(iv) Reverse biased p-n junction has more resistance.

(v) Silver

(vi) If the source of light is linear, then the wavefront is cylindrical where square of the amplitude is inversely proportional to the distance. If the source of light is a point source, then the wavefront is spherical where the amplitude is inversely proportional to the distance. The plane wavefront is appeared at infinite distance from the source and the rays are always parallel straight lines.

(vii) Yes the rays which appear to diverge from the virtual image are real. Hence, they can be focussed on the screen of the camera to form a real image.

Section-B

Answer 2.

  • (i) Potential ∝ (1/r)
  • (ii) Potential is not depend on r.

Answer 3.

(i) In self-pollinated species the seeds are not formed because of self-incompatibility where there is no growth of pollen tube on the stigma of a flower that prevents the fusion of gametes and thereby developing into an embryo. Hence, in such species seed could not be formed.

S.No. Drift velocity Thermal velocity
(a) When a potential difference is applied across a metal, the free electrons drift with a small constant velocity in the direction opposite to the applied field is called drift velocity. The conduction electrons move in all directions with all possible velocities called thermal velocities.
(b) Drift velocity is or the order or 10–6 m/s. It is very small. Thermal velocity is very large and is of the order of 106 m/s.
(c) When the electric field is zero, drift velocity is also zero. Electrons move with thermal velocity even in the absence as well as in the presence of electric field.

OR

240

Answer 4.

  • It states that the line integral of the magnetic field along a closed path is proportional to the current passing through that closed path.
241
  • where µ0 is the permeability of free space and I is the current enclosed by the closed path.

Answer 5.

  • (i) Voltage and current are always in same phase in a purely resistive a.c. circuit. Angle between them is zero.
  • (ii) Voltage leads current by π/2 in a purely inductive a.c. circuit.
  • (iii) Voltage lags behind current by π/2 in a purely capacitive a.c. circuit.

Answer 6.

242

Answer 7.

  • Conditions for sustained interference:
  • (i) The two sources of light must be coherent to emit light of constant phase difference.
  • (ii) The amplitude of electric field vector of interfering wave should be equal to have greater contrast between intensity of constructive and destructive interference. When monochromatic light is replaced by white light, then coloured fringe pattern is obtained on the screen.

Answer 8.

(ii) Formation of energy bands in solids: An isolated atom has well defined energy levels. When large number of such atom get together to form a real soild, their individual energy levels overlap and get completely modified. Instead of discrete value of energy of electrons, the value lies in a certain range. The collection of these closely packed energy levels are said to form an energy band. Two type of such bands formed in solid are called valence band and conduction band. The band formed by filled energy levels is known as valence band, whereas partially filled or unfilled band is known as conduction band. The two bands are generally separated by a gap called energy gap or forbidden gap. Conductors : In case of conductors, electrons fill the conduction band, partially the overlapping of both the bands i.e., valence and conduction band also take place. This shows that no forbidden gap is present.

Insulators : In case of insulator, forbidden gap is very large (> 6 eV). On the other hand, its valence band is fully filled with the electrons, whereas its conduction band is empty.

Semiconductor : In case of semiconductors the conduction band is empty and valence band is filled with electrons. Like insulators, forbidden energy gap is not so large in case of semiconductors. The gap is very small. The energy gap is nearly of 1 eV.

Section-C

Answer 9.

247

Answer 10.

248

OR

Answer 11.

250
251

Answer 12.

252

Answer 13.

(i) When the sun shines upon falling raindrops, an observer with his back towards the sun sees concentric arcs of spectral colours hanging in the sky. These coloured arcs, which have their common centre on the line joining the sun and the observer, are called ‘rainbow’. Usually, two rainbows are seen, one above the other.

The lower one is called the ‘primary’ rainbow and the higher one is called the ‘secondary’ rainbow. The primary rainbow is brighter and narrower, having its inner edge violet and the outer edge red. The secondary rainbow, which is comparatively fainter, has reverse order of colours.

Formation of Primary Rainbow : Rainbows are formed by the dispersion of sunrays in raindrops. The primary rainbow is formed when sunrays, after suffering one internal reflection in the raindrops, emerge at minimum deviation and enters the observer’s eye. In figure, P1 and P2 are two raindrops, E is the observer’s eye and S is the sun. The sunrays fall on the drops parallel to SE. If the rays are deviated (and dispersed) by the drops so as to arrive at the observer, the observer would receive intense light in the those directions in which the rays suffer minimum deviation. It can be shown that he would receive red light in a direction making an angle of 43º, and intense violet light in a direction making an angle of 41º with the line SE produced. The drops sending the intense red and violet light to the observer lie on concentric circles which generate cones of semivertical angles of 43º and 41º respectively with common vertex at E. Thus, the observer sees concentric coloured arcs of which the innermost is violet and the outermost is red. The intermediate colours lie in between. This is the primary rainbow.
Formation of Secondary Rainbow : The secondary fainter rainbow is formed by the sunrays undergoing two internal reflections in the raindrops and emerging at minimum deviation, as occurring in drops S1 and S2 in the figure. The semivertical angles for this bow are 51º for the red rays to 54º for the violet rays. As such, the order of colours is reverse of that in the primary rainbow.

OR

(ii) (a) Both the Lenses are Convex : Suppose two thin convex lenses L1 and L2 of focal lengths f1 and f2 are placed in contact in air having a common principal axis. A point object O is placed on the principal axis at a distance u from the first lens L1. Its image would be formed by the lens L1 alone at I’. distant v’ (say) from L1. Then, from the lens formula, we have,
254
255

Answer 14.

256

Answer 15.

257

Answer 16.

Let e, m, v be the charge, mass and velocity of the electron and r be the radius of the orbit. Positive charge on the nucleus is Ze. In case of hydrogen atom, Z = 1. Centripetal force is provided by electrostatic force of attraction. Therefore,

258
259

Answer 17.

(i) Light emitting diode (LED)

(ii) Semiconductor : In case of semiconductors, the conduction band is empty and valence band is filled with electrons. Like insulators, forbidden energy gap is not so large in case of semiconductors. The gap is very small. The energy gap is nearly of 1 eV.

(iii) The diffusion of electrons from n-region to the p-region of the diode causes depletion region in a p-n junction.

Section-D

Answer 18.

261
262

OR

263

Answer 19.

(a) There are two important radioactive decay laws :

  • (1) In any radioactive transformation, either an a-particle or a b-particle is emitted but it is never, that particles are ejected simultaneously. (i.e., never both or more than one of each kind is emitted)
  • (2) At any instant, the rate of decay of radioactive atoms is proportional to the number of atoms present at that instant.

(b) Let at time t = 0, the number of radioactive atoms present be N0 and at time t, the number be N. Let dN atoms disintegrate in a time dt.
According to Rutherford and Soddy law, we have :

264
265

(a) Transitions labelled A shows absorption lines of Lyman series.

(b) Transitions labelled B show emission lines of Balmer series.

Answer 20.

  • (i) Total internal refection.
  • (ii) The thickness of optical fibers is of the order of micrometers.
  • (iii) For long distance transmissions light in optical fibres enters from one side and comes out from another side like water in a pipe that is why, its popular name is light pipe.
  • (iv) It is called arc.
  • (v) No, the energy carried by the wave remains constant. As it depends on the amplitude of wire. And the frequency remains constant.

ISC 36 Sample Question Papers

All Subjects Combined for Class 12 Exam 2023

The dot mark field are mandatory, So please fill them in carefully
To download the complete Syllabus (PDF File), Please fill & submit the form below.